Curso de Programación en C/Prog78

• Compound Literales
  • Resultado
  • Explicación

Prog78

 1 #include <stdio.h>
 2 
 3 #define COLS 4
 4 
 5 int sum2d( int ar[][COLS], int filas );
 6 int sum( int ar[], int n );
 7 
 8 int main(void)
 9 {
10    int * pt1,
11        (*pt2)[COLS],
12        total1,
13        total2,
14        total3;
15 
16    pt1 = (int [2]) {10, 20};  // compound literales
17    pt2 = (int [2][COLS]) { {1,2,3,-9}, {4,5,6,-8} };
18 
19    total1 = sum( pt1, 2 );
20    total2 = sum2d( pt2, 2 );
21    total3 = sum( (int []) {4,4,4,5,5,5}, 6 );
22    printf( "total1 = %d\n", total1 );
23    printf( "total2 = %d\n", total2 );
24    printf( "total3 = %d\n", total3 );
25 
26    return 0;
27 }
28 
29 int sum( int ar[], int n )
30 {
31   int i;
32   int total = 0;
33 
34   for( i = 0; i < n; i++)
35     total += ar[i];
36 
37   return total;
38 }
39 
40 int sum2d( int ar[][COLS], int filas )
41 {
42   int r;
43   int c;
44   int tot = 0;
45 
46   for( r = 0; r < filas; r++ )
47     for( c = 0; c < COLS; c++ )
48       tot += ar[r][c];
49 
50   return tot;
51 }

Resultado

[rrc@Pridd CClase]$ gcc -Wall -O2 -o Prog78 Prog78.c
[rrc@Pridd CClase]$ ./Prog78
total1 = 30
total2 = 4
total3 = 27
[rrc@Pridd CClase]$ 

=== Explicación ===